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The least n with rad(n) | f(n) whose covering digraph has girth k, for eleven arithmetic functions and k = 2..10: 52 values proved minimal, 38 of them computed here for the first time, with a surgery theorem on the cycle and a certificate deciding m_f(k+1) < m_f(k) without computing it.

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Smallest witnesses by girth for rad(n) | f(n)

New to this? It is explained from scratch, assuming nothing: English · Español

What was found

For a multiplicative function f and an integer n, draw an arc q -> p between primes dividing n whenever p | f(q^e), with q^e the exact power of q in n. Restrict to those n in which every prime receives an arc; such an n always contains a directed cycle, and the length of the shortest one is an invariant of n.

This repository computes the least n whose shortest cycle has length k, for fifteen functions and k = 2, ..., 10: 69 values, each proved minimal, 55 of them computed here for the first time. It also proves a local operation on the cycle that yields an upper bound for the next value, and a certificate derived from it deciding m_f(k+1) < m_f(k) without computing m_f(k+1). The certificate is proved sufficient and not necessary.

Definitions and statements

Let f be multiplicative and local, meaning that q never divides f(q^e). Write rad(n) for the product of the distinct primes of n and

S(f) = { n >= 1 : rad(n) divides f(n) }.

For n = prod q_j^{e_j} in S(f), the covering digraph D_f(n) has the primes of n as vertices and an arc q_i -> q_j (i != j) whenever q_j | f(q_i^{e_i}). Membership in S(f) is equivalent to every vertex having an incoming arc, so D_f(n) always contains a directed cycle. Its girth g_f(n) is the length of the shortest one, and

m_f(k) = min { n in S(f) : g_f(n) = k }.

The fifteen functions are sigma, sigma* (unitary), phi* (unitary totient), sigma** (biunitary), and eleven members of the parametric families

sigma_s(q^e)  = (q^{s(e+1)} - 1)/(q^s - 1),    sigma*_s(q^e) = q^{se} + 1,
phi*_s(q^e)   = q^{se} - 1,

namely sigma_s for s = 2, 3; sigma*_s for s = 2, 3, 5, 6; and phi*_s for s = 2, ..., 6. Every one of them is catalogued, and verify.py checks each that has an OEIS entry against it term by term.

Theorem 1 (shape of a minimum). m_f(k) has exactly k distinct primes, and D_f(m_f(k)) is a pure k-cycle.

Theorem 2 (cutoff lemma). Let n be a witness of girth k and P its largest prime, and let a_f(P) be the least prime power m with P | f(m). Then

n  >=  P * a_f(P) * primorial(k-2).

Consequently, once any witness N of girth k is exhibited, the largest prime of m_f(k) is bounded by the largest P for which the inequality still admits n < N. Enumeration below that bound is exhaustive, so a search that finds nothing proves that nothing exists.

Theorem 3 (surgery). Let n be a witness of girth k whose digraph is the pure cycle q_1 -> ... -> q_k -> q_1, let p be a prime outside it, and let e', a >= 1 satisfy, for some index i:

  1. p | f(q_i^{e'});
  2. q_{i+1} | f(p^a);
  3. q_j does not divide f(q_i^{e'}) for every j != i;
  4. q_j does not divide f(p^a) for every j != i+1;
  5. p does not divide f(q_j^{e_j}) for every j != i.

Then n' = n * q_i^{e'-e_i} * p^a is a witness of girth k+1, whence

m_f(k+1)  <=  m_f(k) * q_i^{e'-e_i} * p^a.

Corollary (certificate). If moreover q_i^{e'} * p^a < q_i^{e_i}, then m_f(k+1) < m_f(k). Deciding this is a finite search that never enumerates primes: the inequality forces e' < e_i, so e' ranges over 1..e_i-1, p over the prime divisors of f(q_i^{e'}), and a over p^a < q_i^{e_i-e'}.

Theorem 4 (the certificate is not necessary). For every k >= 2 and every C > 0 there exists a multiplicative, local f with m_f(k+1) < m_f(k)/C, with m_f(k) squarefree — so that no certificate can fire — and with the cycles of m_f(k) and m_f(k+1) disjoint.

The smallest case, done by hand

Let n = 234 = 2 * 3^2 * 13 and f = sigma:

sigma(2)   = 3            ->   2 -> 3
sigma(3^2) = 13           ->   3 -> 13
sigma(13)  = 14 = 2 * 7   ->   13 -> 2

Every prime receives an arc, so 234 lies in S(sigma), and the arcs form the triangle 2 -> 3 -> 13 -> 2: girth 3. Theorem 2 applied with the witness N = 234 bounds the largest prime of any smaller witness by 13; enumerating those cases leaves nothing. Hence m_sigma(3) = 234 is a minimum, not a record.

For the certificate take f = sigma*, where sigma*(q^e) = q^e + 1, and

m_{sigma*}(5) = 540765225 = 3^2 * 5^2 * 7^5 * 11 * 13.

Cut 7^5 down to 7^3 and insert the prime 43. Conditions 1–5 hold, and 7^3 * 43 < 7^5 because 43 < 49. Therefore m_{sigma*}(6) < m_{sigma*}(5), known before computing it. The witness the construction returns, 474549075 = 3^2 * 5^2 * 7^3 * 11 * 13 * 43, turns out to be m_{sigma*}(6).

Why the statements hold

Theorem 2 is two lower bounds on the same product. The predecessor of P on the cycle contributes a prime power q^e with P | f(q^e), so q^e >= a_f(P) by the definition of a_f; the remaining k-2 primes are pairwise distinct and distinct from P and q, so their product is at least the primorial. The bound is evaluated in integer arithmetic throughout: a floating-point value at the boundary could discard a legitimate witness. Nothing in the argument uses a formula for f, so the lemma holds for every multiplicative function (release 3.4.0); a second bound on the covering cost, obtained by sieving rather than by formula, is about ten times stronger and returns identical minima (RESULT.md, section 4).

Theorem 3 is a count of arcs. In n' the vertices q_j with j != i keep their exponents, so they still point only to q_{j+1}, and condition 5 says they do not point to p; q_i points to p by condition 1 and to no q_j by condition 3; p points to q_{i+1} by condition 2, to no other q_j by condition 4, and not to itself by locality. The digraph is therefore exactly the (k+1)-cycle. Conditions 3–5 are not bookkeeping: dropping them, the same move applied to m_sigma(5) yields 1103602500, whose girth is 2.

Theorem 4 is a construction. Let p_1 < ... < p_{k+1} be the k+1 least primes and let P_1 < ... < P_k be any k primes distinct from them. Set f(p_i^e) = p_{i+1} and f(P_j^e) = P_{j+1} cyclically, and f(q^e) = 1 otherwise. This is multiplicative by construction and local, and its arc set is exactly two disjoint cycles, of lengths k+1 and k. A witness of girth k must therefore contain every P_j, giving m_f(k) = P_1...P_k, while m_f(k+1) = p_1...p_{k+1}; choosing the P_j large makes the ratio unbounded.

Verification

git clone https://github.com/jorgell23-sys/covering-digraph-girth
cd covering-digraph-girth
python verify.py

474 checks, no dependencies, PASS or FAIL on each, exit code 1 if any fails. They re-derive every published value from the definitions, re-prove the reachable ones exhaustively, build the f of Theorem 4 and locate its minima by brute force, compare every function against its OEIS entry term by term, run a brute force that shares no code with the search, and cross-check the count of S(sigma) below 10^9 against Pollack and Pomerance (2012).

What is not claimed

The underlying set is not new: for sigma these are the prime-abundant numbers of Pollack and Pomerance, catalogued as A175200. What is computed here is a graph invariant over that family. Minimality is claimed only for the girths listed; empty cells are unknown, not zero. Whether a witness of every girth exists is untouched. The certificate is one-directional, and Theorem 4 shows it cannot be turned into a characterisation for general f.


New to this? Explained from scratch, with pictures and no background assumed (español).


The terms

Values in bold were computed in this work; every entry is proved minimal.

k sigma sigma* phi* sigma**
2 6 6 12 6
3 234 6615 66825 15925
4 137214 4380453 1120454775 2321865
5 275900625 540765225 1663175056640625 10762773021
6 180141399900 474549075 3321843525
7 7746928876851255 4485174218525 345358414826425
8 31674203849435875 2386830845734335
9 9928651387877145
10 10858178043907173985005
k sigma*_3 sigma*_5 sigma*_6
2 6 6 10
3 2565 2013 207553
4 9933 32175 237133
5 2175327 3910725
6 1278999267
k phi*_3 phi*_4 phi*_5 phi*_6
2 12 6 12 6
3 16891 207553 27951 17501
4 26217125 16099333 161994931 4176227
5 76670443861 2534414641

data/terms.json carries each value with its factorisation, its cycle and the prime bound up to which the enumeration ran. It is regenerated by computation, not transcribed.

Descents

m_f(k+1) < m_f(k) occurs twice among the 64 consecutive pairs with both minima known, both times at the step 5 -> 6:

f step m_f(k) m_f(k+1) ratio
sigma** 5 -> 6 10762773021 3321843525 0.309
sigma* 5 -> 6 540765225 474549075 0.878

The median of the 64 ratios is 587, so the two descents are isolated rather than the tail of a distribution reaching down to 1. The smallest ratio that is not a descent is sigma*_6 from girth 3 to 4, at 1.143, and it lies outside the 5 -> 6 step.

The certificate of Theorem 3 fires on exactly those two pairs and returns the next minimum exactly. Comparing factorisations across the 49 pairs on which the surgery can be tested, it is exact precisely when m_f(k+1) is obtained from m_f(k) by adding one prime and changing one exponent — 49 agreements out of 49. Since m_f(k+1) always has exactly one prime more than m_f(k) by Theorem 1, inserting two vertices cannot produce the next minimum.

Conditions 3–5 have to hold against every vertex of the cycle, which suggests they become harder to satisfy as k grows. Measured over 6661 candidate insertions satisfying conditions 1 and 2, the survival rate drops once — from 7.59 % at girth at most 3 to 1.72 % at girth 4 or more, chi^2 = 138.5 on one degree of freedom — and is then constant: the homogeneity chi^2 is 10.2 on six degrees of freedom. What runs out as k grows is not admissibility but cheap admissibility.

Limits, with numbers

Two terms are bracketed rather than determined:

proved to exceed witness exhibited at primes needed to close it
m_sigma(9) 1.24e21 1.23e24 2.20e9
m_phi*(6) 1.3e18 4.15e22 1.4e10

Both bounds are theorems: the lower one because the search beneath it was exhaustive, the upper one because the witness is exhibited and verified. Closing either requires enumerating the stated number of primes, which does not fit in memory here. Several further terms are out of reach by cost rather than by principle: sigma*_6 at girth 5 and phi*_5 at girth 5 are estimated at 184 and 18 days respectively on six cores, and sigma*_4 at girth 4 would require 1.5e12 primes.

Methods, and how they are cross-checked

Three implementations share no logic. A sieve finds witnesses by exhaustive search over integers and knows nothing about cycles; a constructor builds them from cycles over small primes and never inspects an integer not built from one; the exact search proves minimality via Theorem 2 and accepts nothing without recomputing the girth from the integer itself. They agree on every term that more than one of them can reach.

There is also an external check. The sieve counts 5327 members of S(sigma) below 10^9 excluding n = 1; Pollack and Pomerance count 5328 including it. The agreement tests this code against a peer-reviewed result obtained independently.

Prior-art searches — OEIS and six bibliographic databases, each accompanied by a positive control that does return the relevant literature — are recorded with their dates and query terms in PRIOR_ART.md. Not found is not the same as new.

Contents

RESULT.md full report: statements, proofs, tables, limits
PRIOR_ART.md what was searched for prior work, where and when
verify.py every check, one command, no dependencies
src/arithmetic.py the definitions, in plain Python
src/exact.py proves minimality using the cutoff lemma
src/construct.py builds witnesses from cycles over small primes
src/sieve.py exhaustive search over integers (requires numpy)
src/surgery.py Theorem 3 and its certificate
src/parallel.py the same exact search, split across cores
src/make_terms.py regenerates data/terms.json by computation

A Spanish version of this page: README.es.md.

Citing

See CITATION.cff. Licence: MIT for the code, CC BY 4.0 for text and data.

Author

Jorge Ellena Godoy.

System design and research direction are the author's. The mathematical results were produced by an automated system (Claude, Anthropic) under that direction. All computations were verified by independent implementations and cross-checked against published work. The author is responsible for the correctness of everything published here.

Citing

This work is archived on Zenodo. Cite the concept DOI, which always resolves to the latest version:

Ellena Godoy, Jorge. Smallest witnesses by girth for rad(n) | f(n). Zenodo. https://doi.org/10.5281/zenodo.22288593

DOI

Every release also has its own version DOI; they are all listed on the Zenodo record that the concept DOI resolves to.

About

The least n with rad(n) | f(n) whose covering digraph has girth k, for eleven arithmetic functions and k = 2..10: 52 values proved minimal, 38 of them computed here for the first time, with a surgery theorem on the cycle and a certificate deciding m_f(k+1) < m_f(k) without computing it.

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